14.6

Half-Life and Activity

Chapter contents: Chapter 14: Nuclear and Particle Physics

Unstable nuclei decay. However, some nuclides decay faster than others. For example, radium and polonium, discovered by the Curies, decay faster than uranium. This means they have shorter lifetimes, producing a greater rate of decay. In this section we explore half-life and activity, the quantitative terms for lifetime and rate of decay.

Half-Life

Why use a term like half-life rather than lifetime? The answer can be found by examining Figure 14.6.1, which shows how the number of radioactive nuclei in a sample decreases with time. The time in which half of the original number of nuclei decay is defined as the half-life, t1/2. Half of the remaining nuclei decay in the next half-life. Further, half of that amount decays in the following half-life. Therefore, the number of radioactive nuclei decreases from N to N/2 in one half-life, then to N/4 in the next, and to N/8 in the next, and so on. If N is a large number, then many half-lives (not just two) pass before all of the nuclei decay. Nuclear decay is an example of a purely statistical process. A more precise definition of half-life is that each nucleus has a 50% chance of living for a time equal to one half-life t1/2. Thus, if N is reasonably large, half of the original nuclei decay in a time of one half-life. If an individual nucleus makes it through that time, it still has a 50% chance of surviving through another half-life. Even if it happens to make it through hundreds of half-lives, it still has a 50% chance of surviving through one more. The probability of decay is the same no matter when you start counting. This is like random coin flipping. The chance of heads is 50%, no matter what has happened before.
The figure shows a radioactive decay graph of number of nuclides in thousands versus time in multiples of half-life. The number of radioactive nuclei decreases exponentially and finally approaches zero after about ten half-lives.
Figure 14.6.1. Radioactive decay reduces the number of radioactive nuclei over time. In one half-life t1/2, the number decreases to half of its original value. Half of what remains decay in the next half-life, and half of those in the next, and so on. This is an exponential decay, as seen in the graph of the number of nuclei present as a function of time.
There is a tremendous range in the half-lives of various nuclides, from as short as 10−23 s for the most unstable, to more than 1016 y for the least unstable, or about 46 orders of magnitude. Nuclides with the shortest half-lives are those for which the nuclear forces are least attractive, an indication of the extent to which the nuclear force can depend on the particular combination of neutrons and protons. The concept of half-life is applicable to other subatomic particles. It is also applicable to the decay of excited states in atoms and nuclei.
For simple multiples of half-life (t=t1/2,2t1/2,3t1/2,...,nt1/2), the following intuitive expression relates original N0 and future N amounts.
N=N0(12)n
(14.6.1)
This expression shows that the amount is reduced by half during each half-life. For example, using the data in Figure 1, after three half-lives we see that one-eighth of the original number remains.
t=3t1/2,N0=1,000,000
N=N0(12)n=(1,000,000)(12)3=(1,000,000)(18)=125,000
And after ten half-lives 1/1024 of the original remains.
t=10t1/2,N0=1,000,000
N=N0(12)n=(1,000,000)(12)10=(1,000,000)(11024)=977
For an arbitrary time, not just a multiple of the half-life, the exponential relationship shown below is generally used. The following equation gives the quantitative relationship between the original number of nuclei present at time zero N0 and the number N at a later time t:
N=N0e−λt,
(14.6.2)
where e=2.71828... is the base of the natural logarithm, and λ is the decay constant for the nuclide. The shorter the half-life, the larger is the value of λ, and the faster the exponential e−λt decreases with time. The relationship between the decay constant λ and the half-life t1/2 is
λ=ln(2)t1/2≈0.693t1/2.
(14.6.3)
To see how the number of nuclei declines to half its original value in one half-life, let t=t1/2 in the exponential in the equation N=N0e−λt. This gives N=N0e−λt=N0e−0.693=0.500N0.
Radioactive dating is a clever use of naturally occurring radioactivity. Its most famous application is carbon-14 dating. Carbon-14 has a half-life of 5700 years and is produced in a nuclear reaction induced when neutrons produced by cosmic rays strike N14 in the atmosphere. Radioactive carbon has the same chemistry as stable carbon, and so it mixes into the ecosphere, where it is consumed and becomes part of every living organism. Carbon-14 has an abundance of 1.3 parts per trillion of normal carbon. Thus, if you know the number of carbon nuclei in an object (perhaps determined by mass and Avogadro’s number), you multiply that number by 1.3×10−12 to find the number of C14 nuclei in the object. When an organism dies, carbon exchange with the environment ceases, and C14 is not replenished as it decays. By comparing the abundance of C14 in an artifact, such as mummy wrappings, with the normal abundance in living tissue, it is possible to determine the artifact’s age (or time since death). Carbon-14 dating can be used for biological tissues as old as 50 or 60 thousand years, but is most accurate for younger samples, since the abundance of C14 nuclei in them is greater. Very old biological materials contain no C14 at all. There are instances in which the date of an artifact can be determined by other means, such as historical knowledge or tree-ring counting. These cross-references have confirmed the validity of carbon-14 dating and permitted us to calibrate the technique as well. Carbon-14 dating revolutionized parts of archaeology and is of such importance that it earned the 1960 Nobel Prize in chemistry for its developer, the American chemist Willard Libby (1908–1980).
One of the most famous cases of carbon-14 dating involves the Shroud of Turin, a long piece of fabric purported to be the burial shroud of Jesus (see Figure 14.6.2). This relic was first displayed in Lirey, France, in the 1350s. Its remarkable negative imprint of an apparently crucified body resembles the then-accepted image of Jesus, and so the shroud was never disregarded completely and remained controversial over the centuries. Carbon-14 dating was not performed on the shroud until 1988, when the process had been refined to the point where only a small amount of material needed to be destroyed. Samples were tested at three independent laboratories, each receiving a shroud sample and control samples. All three laboratories obtained medieval dates. The following example uses a rounded value of 92% to illustrate the dating calculation (see Example 14.6.1).
Two views of the face image on the Shroud of Turin: a faint image on the cloth and its higher-contrast photographic negative.
Figure 14.6.2. Part of the Shroud of Turin, which shows a remarkable negative imprint likeness of Jesus complete with evidence of crucifixion wounds. The shroud first surfaced in the 14th century and was carbon-14 dated in 1988. It has not been determined how the image was placed on the material. (credit: Butko, Wikimedia Commons)
Example 14.6.1

How Old Is the Shroud of Turin?

Calculate the age of the Shroud of Turin using the approximation that the amount of C14 found in it is 92% of that in living tissue.
Strategy
Knowing that 92% of the C14 remains means that N/N0=0.92. Therefore, the equation N=N0e−λt can be used to find λt. We also know that the half-life of C14 is 5700 y, and so once λt is known, we can use the equation λ=0.693t1/2 to find λ and then find t as requested. Here, we postulate that the decrease in C14 is solely due to nuclear decay.
Solution
Solving the equation N=N0e−λt for N/N0 gives
NN0=e−λt.
Thus,
0.92=e−λt.
Taking the natural logarithm of both sides of the equation yields
ln0.92=−λt
so that
−0.0834=−λt.
Rearranging to isolate t gives
t=0.0834λ.
Now, the equation λ=0.693t1/2 can be used to find λ for C14. Solving for λ and substituting the known half-life gives
λ=0.693t1/2=0.6935700y.
We enter this value into the previous equation to find t:
t=0.08340.6935700y=686 y.
Discussion
This simplified calculation dates the material to about AD 1300, using 1988 as the measurement year. The published study reported a calibrated date range of AD 1260–1390 with at least 95% confidence. Calibration accounts for changes in atmospheric carbon-14 over time. The medieval date is consistent with the first record of the shroud’s existence and inconsistent with the period in which Jesus lived.
There are other forms of radioactive dating. Rocks, for example, can sometimes be dated based on the decay of U238. The decay series for U238 ends with Pb206, so that the ratio of these nuclides in a rock is an indication of how long it has been since the rock solidified. The original composition of the rock, such as the absence of lead, must be known with some confidence. However, as with carbon-14 dating, the technique can be verified by a consistent body of knowledge. Since U238 has a half-life of 4.5×109 y, it is useful for dating only very old materials, showing, for example, that the oldest rocks on Earth solidified about 3.5×109 years ago.

Activity, the Rate of Decay

What do we mean when we say a source is highly radioactive? Generally, this means the number of decays per unit time is very high. We define activity R to be the rate of decay expressed in decays per unit time. In equation form, this is
Activity is an expected decay rate. A count measured during a finite interval fluctuates statistically, and a detector may register only some of the decays.
R=ΔNΔt
(14.6.4)
where ΔN is the number of decays that occur in time Δt. The SI unit for activity is one decay per second and is given the name becquerel (Bq) in honor of the discoverer of radioactivity. That is,
1Bq=1decay/s.
(14.6.5)
Activity R is often expressed in other units, such as decays per minute or decays per year. One of the most common units for activity is the curie (Ci), originally based on the activity of 1 g of Ra226, in honor of Marie Curie’s work with radium. The definition of curie is
1Ci=3.70×1010 Bq,
(14.6.6)
or 3.70×1010 decays per second. A curie is a large unit of activity, while a becquerel is a relatively small unit. 1MBq≈27.0microcuries(μCi). In countries like Australia and New Zealand that adhere more to SI units, most radioactive sources, such as those used in medical diagnostics or in physics laboratories, are labeled in Bq or megabecquerel (MBq).
Intuitively, you would expect the activity of a source to depend on two things: the amount of the radioactive substance present, and its half-life. The greater the number of radioactive nuclei present in the sample, the more will decay per unit of time. The shorter the half-life, the more decays per unit time, for a given number of nuclei. So activity R should be proportional to the number of radioactive nuclei, N, and inversely proportional to their half-life, t1/2. In fact, your intuition is correct. It can be shown that the activity of a source is
R=0.693Nt1/2
(14.6.7)
where N is the number of radioactive nuclei present, having half-life t1/2. This relationship is useful in a variety of calculations, as the next two examples illustrate.
Example 14.6.2

How Great Is the C14 Activity in Living Tissue?

Calculate the activity due to C14 in 1.00 kg of carbon found in a living organism. Express the activity in units of Bq and Ci.
Strategy
To find the activity R using the equation R=0.693Nt1/2, we must know N and t1/2. The half-life of C14 can be found in Appendix B, and was stated above as 5700 y. To find N, we first find the number of C12 nuclei in 1.00 kg of carbon using the concept of a mole. As indicated, we then multiply by 1.3×10−12 (the abundance of C14 in a carbon sample from a living organism) to get the number of C14 nuclei in a living organism.
Solution
One mole of carbon has a mass of 12.0 g, since it is nearly pure C12. (A mole has a mass in grams equal in magnitude to A found in the periodic table.) Thus the number of carbon nuclei in a kilogram is
N(C12)=6.02×1023mol−112.0g/mol×(1000 g)=5.02×1025.
So the number of C14 nuclei in 1 kg of carbon is
N(C14)=(5.02×1025)(1.3×10−12)=6.52×1013.
Now the activity R is found using the equation R=0.693Nt1/2.
Entering known values gives
R=0.693(6.52×1013)5700y=7.93×109y−1,
or 7.93×109 decays per year. To convert this to the unit Bq, we simply convert years to seconds. Thus,
R=(7.93×109y−1)1.00y3.16×107s=251Bq,
or 251 decays per second. To express R in curies, we use the definition of a curie,
R=251Bq3.7×1010 Bq/Ci=6.78×10−9 Ci.
Thus,
R=6.78nCi.
Discussion
Our own bodies contain kilograms of carbon, and it is intriguing to think there are hundreds of C14 decays per second taking place in us. Carbon-14 and other naturally occurring radioactive substances in our bodies contribute to the background radiation we receive. The small number of decays per second found for a kilogram of carbon in this example gives you some idea of how difficult it is to detect C14 in a small sample of material. If there are 251 decays per second in a kilogram, then there are 0.251 decays per second in a gram of carbon in living tissue. To observe this, you must be able to distinguish decays from other forms of radiation, in order to reduce background noise. This becomes more difficult with an old tissue sample, since it contains less C14, and for samples more than 50 thousand years old, it is impossible.
Human-made (or artificial) radioactivity has been produced for decades and has many uses. Some of these include medical therapy for cancer, medical imaging and diagnostics, and food preservation by irradiation. It is clear that radiation is hazardous. A number of tragic examples of this exist, one of the most disastrous being the meltdown and fire at the Chernobyl reactor complex in the Ukraine (see Figure 14.6.3). Several radioactive isotopes were released in huge quantities, contaminating many thousands of square kilometers and directly affecting hundreds of thousands of people. The most significant releases were of I131, Sr90, Cs137, Pu239, U238, and U235. Estimates are that the total amount of radiation released was about 100 million curies.

Human and Medical Applications

A person holding a hand held radiation detector near the Chernobyl reactor.
Figure 14.6.3. The Chernobyl reactor. About 30 workers died within weeks of the accident. Radiation exposure also increased thyroid-cancer incidence among people exposed as children or adolescents. While the accident was due to a series of human errors, the cleanup efforts were heroic. Most of the immediate fatalities were firefighters and reactor personnel. (credit: Elena Filatova)
Example 14.6.3

What Mass of Cs137 Escaped Chernobyl?

It is estimated that the Chernobyl disaster released 6.0 MCi of Cs137 into the environment. Calculate the mass of Cs137 released.
Strategy
We can calculate the mass released using Avogadro’s number and the concept of a mole if we can first find the number of nuclei N released. Since the activity R is given, and the half-life of Cs137 is found in Appendix B to be 30.2 y, we can use the equation R=0.693Nt1/2 to find N.
Solution
Solving the equation R=0.693Nt1/2 for N gives
N=Rt1/20.693.
Entering the given values yields
N=(6.0 MCi)(30.2y)0.693.
Converting curies to becquerels and years to seconds, we get
N=(6.0×106 Ci)(3.7×1010 Bq/Ci)(30.2y)(3.16×107 s/y)0.693=3.1×1026.
One mole of a nuclide XA has a mass of A grams, so that one mole of Cs137 has a mass of 137 g. A mole has 6.02 ×1023 nuclei. Thus the mass of Cs137 released was
m=(137g6.02 ×1023)(3.1×1026)=70×103 g=70kg.
Discussion
While 70 kg of material may not be a very large mass compared to the amount of fuel in a power plant, it is extremely radioactive, since it only has a 30-year half-life. Six megacuries (6.0 MCi) is an extraordinary amount of activity but is only a fraction of what is produced in nuclear reactors. Similar amounts of the other isotopes were also released at Chernobyl. Although the chances of such a disaster may have seemed small, the consequences were extremely severe, requiring greater caution than was used.
Activity R decreases in time, going to half its original value in one half-life, then to one-fourth its original value in the next half-life, and so on. Since R=0.693Nt1/2, the activity decreases as the number of radioactive nuclei decreases. The equation for R as a function of time is found by combining the equations N=N0e−λt and R=0.693Nt1/2, yielding
R=R0e−λt,
(14.6.8)
where R0 is the activity at t=0. This equation shows exponential decay of radioactive nuclei. For example, if a source originally has a 1.00-mCi activity, it declines to 0.500 mCi in one half-life, to 0.250 mCi in two half-lives, to 0.125 mCi in three half-lives, and so on. For times other than whole half-lives, the equation R=R0e−λt must be used to find R.
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